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In a Young’s double slit experiment, the...

In a Young’s double slit experiment, the ratio of the slit’s width is 4 : 1. The ratio of the intensity of maxima to minima, close to the central fringe on the screen, will be:

A

`9 : 1 `

B

` ( sqrt(3) + 1)^(4) : 16`

C

`4 : 1 `

D

` 25 : 9`

Text Solution

Verified by Experts

The correct Answer is:
A
`I prop W `
`(I_(1))/( I_(2)) = (4)/(1)`
`(I_("max"))/(I_("min")) = ((sqrt(I_(1)) + sqrt(I_(2)))/(sqrt(I_(1) - sqrt(I_(2)))))^(2) = (( sqrt(I_(1) // I_(2)) + 1)/(sqrt(I_(1)//I_(2)) -1))^(2)`
`= (( sqrt(4) + 1)/( sqrt(4) - 1))^(2) = (( 2 + 1)/( 2 - 1))^(2) = ((3)/(1))^(2) = (9)/(1)`
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