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The intensity of gamma radiation from a ...

The intensity of gamma radiation from a given source is `I`
On passing through `36 mm` of lead , it is reduced to `(1)/(8)` . The thickness of lead which will reduce the intensity to `(1)/(2)` will be

A

18 mm

B

12 mm

C

6 mm

D

9 mm

Text Solution

Verified by Experts

The correct Answer is:
B
Intensity `I = I_(0) e^(-mu d) rArr - mu d = log ((I)/(I_(0)))`
`rArr - mu xx 36 = log ((I // 8)/(I)) ` . . . (i)
`rArr - mu xx d = log (( I // 2)/( I)) ` . . . (ii)
From (I) & (ii)
`(36)/( d) = (log ((1)/(8)))/(log ((1)/(2))) rArr d = (36)/(3) = 12 m m `
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