The magnetic field of an electromagnetic wave is given by:
`oversetB=1.6xx10^(-6)cos(2xx10^(7)z+6xx10^(15)t)(2hati+hatj)(Wb)/m^(2)`
The associated electric field will be:

Options

A. ` vec(E) = 4 . 8 xx 10^(2) cos ( 2 xx 10^(7) z + 6 xx 10 ^(15) t) ( hat(i) - 2 hat(j)) (V)/(m)`
B. ` vec(E) = 4 . 8 xx 10^(2) cos ( 2 xx 10^(7) z - 6 xx 10 ^(15) t) ( -2hat(j) + hat(i)) (V)/(m)`
C. ` vec(E) = 4 . 8 xx 10^(2) cos ( 2 xx 10^(7) z + 6 xx 10 ^(15) t) ( -hat(i) + 2 hat(j)) (V)/(m)`
D. ` vec(E) = 4 . 8 xx 10^(2) cos ( 2 xx 10^(7) z - 6 xx 10 ^(15) t) ( 2hat(i) + 2 hat(j)) (V)/(m)`

Answer

A

Explanation

Amplitude of electric field , `R = B_(0) C `
`= 1.6 xx 10 ^(-6) xx sqrt() xx 3 xx 10 ^(8)`
` = 4 . 8 xx 10^(2) sqrt(5) V// m`
also ` vec (E) xx vec (B) ` is along ` - hat(k)` (the direction of propagation)
`rArr vec(E) = 4.8 xx 10^(2) cos ( 2 xx 10^(7) z + 6 xx 10^(15) t) ( - hat(i) + 2 hat(j)) V// m`