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A "50 W m"^(-2) energy density of sunlig...

A `"50 W m"^(-2)` energy density of sunlight is incident normally on the surface of a solar panel. Some part of incident energy `(25%)` is reflected from the surface and the rest is absorbed. The force exerted on `1m^(2)` surface area will be close to
`(c=3xx10^(8)ms^(-1))`

A

` 35 xx 10 ^(-8) N`

B

` 10 xx 10^(-8) N`

C

` 15 xx 10^(-8) N`

D

` 20 xx 10^(-8) N`

Text Solution

Verified by Experts

The correct Answer is:
D
`P = (I)/(c) (1 + r)`
`P = (1 . 25 xx 50)/( 3 xx 10^(8))`
`F = (1 . 25 xx 50)/( 3 xx 10^(8)) xx 1 = (12 . 5 xx 50)/( 3 xx 10^(8)) = (62 .5)/( 3) xx 10 ^(-8)`
`= 20 . 8 xx 10^(-8) N`
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