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If 2 .5 xx 10^(-6) N average force is ex...

If `2 .5 xx 10^(-6) N` average force is exerted by a light wave on a non-reflecting surface of `30 cm^(2)` area during 40 minutes of time span, the energy flux of light just before it falls on the surface is `"____________" W //cm^(2)`. ( Round off to the Nearest Integer )
(Assume complete absorption and normal incidence conditions are there )

Text Solution

Verified by Experts

The correct Answer is:
25

`F = (IA)/( c)`
`F = (P)/(c)`
`2 . 5 xx 10 ^(-6) = (P)/( 3 xx 10^(8))`
`7 . 5 xx 10 ^(2) = P`
Energy flux ` = (P)/(A) = (7 . 5 xx 10^(2))/(30) = 25 W//m^(2)`
Energy flux = 25 `W//m^(2)`
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