The atomic weights of two alements A and B are 40 and 80 reapectively. If x g of A contains y atoms, how many atoms are present in 2x g of B?

Options

A. `(y)/(2)`
B. `(y)/(4)`
C. y
D. 2y

Answer

C

Explanation

Number of moles of `A = (x)/(40)`
Number of atoms `A = (x)/(40) xx ` Avogadro no = y (say)
Or `x = (40 y)/("Avogadrono")`
Number of moles of B `= (2x)/(80)`
Number of atoms B
` = (2x)/(80) xx ` Av. No `= (2)/(80) xx (40 y)/("Av. No") xx ` Av . no = y