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1.5g CdCl(2) was formed to contain 0.9g ...

1.5g `CdCl_(2)` was formed to contain 0.9g Cd. Calculate MO, the atomic weight of Cd.

A

118

B

112

C

106.5

D

53.25

Text Solution

Verified by Experts

The correct Answer is:
C
Let m be the atomic wt. of Cd.
Proportion of Cd in the compound will be equal
So `(m + 2(35.5))/(m) = (1.5)/(0.9)`
` m = 106.5`
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