A metal M of equivalent mass E forms an oxide of molecular formula `M_(x)O_(y)`. The atomic mass of the metal is given by the correct equation.

Options

A. 2E(y/x)
B. xyE
C. E/y
D. y/E

Answer

A

Explanation

Oxide of M = ` M_(x)O_(y)`
`= M^(y)O^(x-) rArr M^(y//x) O^(-1)`
` = M^(2y//x)O^(-2)` (Valency of O is -2)d
Valency of M,V = 2y/x
Let m be the atomic mass of M.
Thus `E = (m)/(v)`
`m = E(2y//x)`