The weight of a molecule of the compound`C_(60)H_(122)` is

Options

A. `1.4xx10^(-21) g`
B. `1.09 xx 10^(-21) g`
C. `5.025 xx 10^(23) g `
D. `16.023 xx 10^(23) g`

Answer

A

Explanation

Molecular weight of `C_(60) H_(122) = 12 xx 60+ + 122 xx 1`
`= 720 + 122 = 842`
`because 6 xx 10^(23)` molecule `C_(60)H_(122)` has mass = 842g
`therefore ` 1 molecule `C_(60) H_(122)` has mass
`(842)/(6 xx 10^(23)) = 140.333 xx 10^(-23) g = 1.4 xx 10^(-21) g`