What is the weight of oxygen required for the complete combustion of 2.8 kg of ethylene?

Options

A. 2.8 kg
B. 6.4 kg
C. 9.6kg
D. 96 kg

Answer

C

Explanation

`underset(28g)underset("Ethylene")(C_(2)H_(4)) + underset(96g)(3O_(2)) to 2CO_(2) + 2H_(2)O`
The weight of oxygen required for complete combustion of 28g ethylene `rArr ` 96 g.
`therefore ` Weight of oxygen required for combustion of 2.8kg ethylene
` = (96 xx 2.8 xx 1000)(28 xx 1000) kg = 9.6kg`