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Complete combustion of 0.858 g of compou...

Complete combustion of 0.858 g of compound X gives 2.63 g of `CO_(2)` and 1.28 g of` H_(2)`O. The lowest molecular mass X can have

A

75

B

93.5

C

100

D

80

Text Solution

Verified by Experts

The correct Answer is:
A
`% C = (12)/(44) xx (W_(co_(2))/(W)) xx 100 = (12)/(44) xx (2.63)/(0.858) xx 100 = 83.6%`
`%H = (2)/(18) xx (W_(H_(2)O))/(W) xx 100 = (2)/(18) xx (1.28)/(858) xx 100 = 16.4%`
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