Home
Class 11
CHEMISTRY
4 g of copper was dissolved in concentra...

4 g of copper was dissolved in concentrated nitric acid. The copper nitrate solutio on strong heating gave 5g of its oxide. The equivalent weight of copper is

A

23

B

32

C

12

D

20

Text Solution

Verified by Experts

The correct Answer is:
B

In 5 g CuO, 4 g Cu and 1 g O be present.

Empirical formula = CuO of oxide
In this oxide, oxidation no. of Cu = + 2
Equivalent weight ` = ("Molecular weight")/("Oxidation no.") = (63.5)/(2) ~~ 31.75` but Equivalent weight should be an integral no. = 32.
Promotional Banner

Similar Questions

Explore conceptually related problems

1.60 g of a metal was dissolved in HNO_3 to prepare its nitrate. The nitrate salt on strong heating gave 2g oxide. The equivalent mass of metal is:

0.5g of a metal on oxidation gave 0.7 g of its oxide. The equivalent weight of the metal is -

1.60g of a metal was dissolved in HNO_(3) to prepare its nitrate.The nitrate on strong heating gives 2g oxide.The equivalent weight of metal is 4 x,then x is

In an experiment 2.16 g of copper was dissolved in nitric acid followed by ignition of the nitrate, which gave 2.70 g of copper oxide. In another experiment 1.46 g of copper on heating in a curent of air gave 1.83 g of copper. Oxide. The percentage of copper in copper oxide is _____________ and the abvoe data illustrate the law of ____________.

2,75 g of cupric oxide was reduced by heating in a current of hydrogen and the weight of copper that remained was 2.196 g. Another experiment, 2.358 g of copper was dissolved in nitric acid and the resulting copper nitrate converted into cupric oxide by ignition. The weight of cupric oxide formed was 2.952 g. Show that these results illustrate law of constant composition.