The molar mass of `CaCO_(3)` is 100 g. The maximum amount of carbon dioxide that can be liberated on heating 25 g of `CaCO_(3)` is -

Options

A. 11g
B. 55g
C. 22g
D. 2.2g

Answer

A

Explanation

`25g CaCO_(3) rArr (25)/(100) = (1)/(4)` mole of `CaCO_(3)`
`CaCO_(3) to CaO + CO_(2)`
` because ` 1 mole `CaCO_(3)` produce 1 mole `CO_(2)`
`therefore (1)/(4) ` mole `CaCO_(3)` produce `(1)/(4)` mole `CO_(2)`
and `(1)/(4)` mole `CO_(2) = (1)/(4) xx 44g ` of `CO_(2) = 11g`