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The number of water molecules present in...

The number of water molecules present in a drop of water (volume 0.0018 ml) density = 1 `gmL^-1` at room temperature is

A

`6.023 xx 10^(19)`

B

`1.084 xx 10^(18)`

C

`4.84 xx 10^(17)`

D

`6.023 xx 10^(23)`

Text Solution

Verified by Experts

The correct Answer is:
A
Density `= ("Mass")/("Volume") ,1 = (g)/(mL) ` or g = mL
`0.0018 mL = 0.0018 g`
No.of moles ` = ("weight")/("Molecular weight") = (0.0018)/(18) = 1 xx 10^(-4)`
`therefore` No. of water molecules `=6.023 xx 10^(23) xx 1 xx 10^(-4) = 6.023 xx 10^(19)`
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