The total number of electrons in 18 mL of water `("density = 1 g "mL^(-)1)` is

Options

A. `6.02 xx 10^(23)`
B. `6.02 xx 10^(25)`
C. `6.02 xx 10^(24)`
D. `6.02 xx 18 xx 10^(23)`

Answer

C

Explanation

`18 mL H_(2)O = 18 g H_(2)O = 1 "mol" ` ( `because ` d = 1g/ mL and v = 18 mL)
` = 6.02 xx 10^(23)` molecules
since 1 molecules of water contains
`10 bar(e) [2bar(e)"of" H + 8bar(e) "of" O]`
Thus
`6.02 xx 10^(23)` molecules will contain `= 10 xx 6.02 xx 10^(23) bar(e)`
` =6.02 xx 10^(24) bar(e)`