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The number of formula units of calcium f...

The number of formula units of calcium fluoride `CaF_(2)` present in 146.4 g of `CaF_(2)` (The molar mass of `CaF_(2)` is `78.08` g/mol) is

A

`1.129 xx 10^(24) CaF_(2)`

B

`1.146 xx 10^(24) CaF_(2)`

C

`7.808 xx 10^(24) CaF_(2)`

D

`1.877 xx 10^(24) CaF_(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
Number of moles of `CaF_(2) =(146.4)/(78.08) = 1.875`
`therefore ` No. of formula units ` = 1.875 xx N_(A)`
` = 1.875 xx 6.022 xx 10^(23) = 11.29 xx 10^(23) = 1.129 xx 10^(24)`
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