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Sodium nitrate on reduction with Zn in p...

Sodium nitrate on reduction with Zn in presence of NaOH solution produces `NH_(3)`. Mass of sodium nitrate absorbing 1 mole of electron will be .

A

7.75

B

10.625

C

8

D

9.875

Text Solution

Verified by Experts

The correct Answer is:
B
Ammonia is formed by reduction of nitrates and nitrites with Zn and NaOH. Zn and caustic soda produce nascent hydrogen which reacts with nitrates to form ammonia.
`NaNO_(3) + 8H^(+) + 8e overset(Zn//NaOH) to NaOH + NH_(3) + 2H_(2)O`
From the equation
Mass of `NaNO_(3)` absorbing 8 moles of electron = 85g
`therefore` Mass of `NaNO_(3)` absorbing 1 mole of electron ` = (85)/(8) = 10.625g`
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