In the complex with formula `MCl_(3).4H_(2)O` the co-ordination number of the metal M is six. And there is a no molecule of hydration in it. The volume of 0.1 M `AgNO_(3)` solution needed to precitate the free chloride ions in 200 ml of 0.01 M solution of the complex is

Options

A. 40 mL
B. 20 mL
C. 60 mL
D. 80 mL

Answer

B

Explanation

The complex with formula `MCl_(3).4H_(2)O`, with no molecule of hydration is `[MCl_(2)(H_(2)O)_(4)]Cl` , so one chlorine is ionisable .
`therefore ` No. of equivalent of `Ag^(+) = ` Mo. Of equivalent of `Cl^(-)` in solution ` = 0.1xx V = 200 xx 0.1`
` therefore V = (2)/(0.1) = 20 mL`