For the reaction `Fe_(2)O_(3)+3CO to 2Fe+3CO_(2)`, the volume of carbon monoxide required to reduce one mole of ferric oxide is

Options

A. `67.2 dm^(3)`
B. `11.2 dm^(3)`
C. `22.4 dm^(3)`
D. `44.8 dm^(3)`

Answer

A

Explanation

`Fe_(2)O_(3) + 3CO to 2Fe + 3CO_(2)`
`{:("1 vol.","3 vol.","2vol.","3 vol."),("1 mol.", "3 mol.","2 mol.", "3 mol."):}`
(`therefore` vol % = mol %)
One gram mol of any gas occupies 22.4 litre at NTP. 1 mol of `Fe_(2)O_(3)` requires 3 mol of CO for its reduction i.e., 1 mol of `Fe_(2)O_(3)` requires ` 3 xx 22.4 ` litres or `67.2 dm^(3)` Co to get itself reduced .