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Calculate the mass of BaCO(3) produced w...

Calculate the mass of `BaCO_(3)` produced when excess `CO_(2)` is bubbled through a solution containing `0.205` moles of `Ba(OH)_(2)`.

A

81g

B

40.5g

C

20.25g

D

162 g

Text Solution

Verified by Experts

The correct Answer is:
B
`Ba(OH_(2)) + CO_(2) to BaCO_(3) +H_(2)O`
Atomic wt. of `BaCO_(3) = 137+12+16 xx 3 = 197`
No.of mole ` = ("wt.of substance")/("mol wt.")`
`because` 1 mole of `Ba(OH)_(2)` gives 1 mole of `BaCO_(3)`
`therefore` 0.205 mole of `Ba(OH)_(2)` will give 0.205 mole of `BaCO_(3)`
`therefore ` wt.of 0.205 mole of `BaCO_(3)` will be
` 0.205 xx 197 = 40.358 gm ~~ 40.5 g `
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