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A mixture of CaCl(2) and NaCl weighing ...

A mixture of `CaCl_(2)` and NaCl weighing 4.44g is treated with solution carbonate solution to precipitate all the `Ca^(2+)` ions as calcium carbonate . The calcium carbonate so obtained is heated strongly to get 0.25 g of CaO. The percentage of NaCl in the mixture (Atomic mass of Ca = 40) is.

A

75

B

30.5

C

25

D

69.4

Text Solution

Verified by Experts

The correct Answer is:
A
Concerned reaction is `underset(100 g)(CaCO_(3)) overset(Delta) to underset(56g)(CaO) + CO_(2)`
56 g of CaO is obtained from 100 g of `CaCO_(3)`
0.56g of CaO is obtained by `(100)/(56) xx 0.56 = 1`g of `CaCO_(3)`
we know that
`underset(111g)(CaCl_(2)) + Na_(2)CO_(3) to underset(100g)(CaCO_(3)) + 2NaCl`
100g of `CaCO_(3)` is obtained by 111g of `CaCl_(2)`
Weight of NaCl= 4.44 - 1.11 = 3.33g
% age of NaCl `= (3.33)/(4.44) xx 100 = 75%`
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