The formula weight of an acid is `82.0.100 cm^(3)` of a solution of this acid containing `39.0 g` of the acid per litre were completely neutralised by `95.0 cm^(3)` of aqueous `NaOH` containing `40.0 g` of `NaOH` per litre. What is the basicity of the acid?

Answer

2

Explanation

Suppose the equivalent weight of the acid = E
`therefore` Normality of the acid solution `=(39g L^(-1))/E`
Eq. Wt of NaOH = 40
`therefore` Normality of NaOH solution `=(40 g L^(-1))/40 = 1 N`
Applying `underset("Acid")(N_(1)V_(1)) = underset("NaOH")(N_(2)V_(2))`
`39/E xx 100 = 1 xx 95` or E = 41.0
`therefore` Basicity of the acid `=("Formula wt")/("Eq. wt") = 82.0/41.0 = 2`