Haemoglobin contains 0.25% iron by weight. The molecular weight of haemoglobin is 896000. Calculate the number of iron atom per molecule of haemoglobin.

Answer

4

Explanation

Iron present in 100 g haemoglobin = 0.25 g And, iron present in 89600 g haemoglobin.
`= (0.25 xx 89600)/100 = 224 g Fe`
1 mole of `N_(A)` molecules of haemoglobin has 224 g Fe or g-atoms of Fe `= (224//56) = 4`
= 4g-atom of Fe = 4N atom of Fe
`therefore` 1 molecule of haemoglobin = 4 atom of Fe.