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5 moles of AB(2) weigh 125 xx 10^(-3) kg...

5 moles of `AB_(2)` weigh `125 xx 10^(-3)` kg and 10 moles of `A_(2)B_(2)` weigh `300 xx 10^(-3)` kg. What is the sum of molar mass of A `(M_(A))` and molar mass of `B(M_(B))` in `g "mol"^(-1)` ?

A

`M_(A) = 10 xx 10^(-3)` and `M_(B) = 5 xx 10^(-3)`

B

`M_(A) = 25 xx 10^(-3)` and `M_(B) = 50 xx 10^(-3)`

C

`M_(A) = 5 xx 10^(-3)` and `M_(B) = 10 xx 10^(-3)`

D

`M_(A) = 50 xx 10^(-3)` and `M_(B) = 25 xx 10^(_3)`

Text Solution

Verified by Experts

The correct Answer is:
C
Mass of 1 mole of `AB_(2) : M_(A) + 2M_(B) = 25 xx 10^(-3) kg`
Mass of 1 mole of `A_(2)B_(2) : 2M_(A) + 2M_(B) = 30 xx 10^(-3) kg`
`therefore M_(A) = 5 xx 10^(-3) kg//mol`
`M_(B) = 10 xx 10^(-3)` kg/mol
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