1g of a carbonate (M(2)CO(3)) on treatme...

`1g` of a carbonate `(M_(2)CO_(3))` on treatment with excess `HCl` produces `0.01186` mole of `CO_(2)`. The molar mass of `M_(2)CO_(3)` in `g mol^(-1)` is

A

84.3

B

118.6

C

11.86

D

1186

Verified by Experts

The correct Answer is:

A

`M_(2)CO_(3) + 2HCl to 2MCl + H_(2)O + CO_(2)`
`M_(0)` = Molar mass of `M_(2)CO_(3)`
`1/M_(0) = 0.01186`
`M_(0) = 84.3` g/mol

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