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What would be the molality of 20% (mass/...

What would be the molality of 20% (mass/mass) aqueous solution of KI ?
(molar mass of KI `= 166 g mol^(-1)`)

A

1.35

B

1.08

C

1.48

D

1.51

Text Solution

Verified by Experts

The correct Answer is:
D
20 g Kl is present in 100 g solution
Weight of solvent = 100 - 20 = 80 g
Moles of solute = `20/166`
Molality (m) = `20/(166 xx 80) xx 1000 = 1.51`
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