Aluminium chloride exists as a dimer, `Al_(2)Cl_(6)` in solid state as well as in solution of non-polar solvents such as benzene. When dissolved in water, it gives :

Options

A. `[Al(OH)_6]^(3-) + 3HCl`
B. `[Al (H_2 O)_6 ]^(3+) + 3Cl^(-)`
C. `Al^(3+) + 3Cl^-`
D. `Al_2 O_3 + 6HCl`

Answer

B

Explanation

`Al_2 Cl_6 + 12 H_2 O hArr 2[Al (H_2 O)_6]^(3+) + 6Cl^-`.