Area of Triangle

Consider the following statements : 1. Let D be a point on the side BC of a triangle ABC: If area of triangle ABD = area of triangle ACD, then for all points O on AD, area of triangle ABO = area of triangle ACO. 2. If G is the point of concurrence of the medians of a triangle ABC, then area of triangle ABG = area of triangle BCO = area of triangle ACG. Which of the above statements is/are correct?

ABC is a triangle in which D is the midpoint of BC and E is the midpoint of AD. Which of the following statements is/are correct? 1. The area of triangle ABC is equal to four times the area of triangle BED. 2. The area of triangle ADC is twice the area of triangle BED. Select the correct answer using the code given below.

ABCD is rectangle.P and Q are points on AB and BC respectively such that the area of triangle APD=5, area of triangle PBQ=4 and area of triangle QCD=3, all areas in square units.Then the areaof the triangle DPQ in square units is

Area of a triangle

Area of quadrilateral ABCD =Area of Delta ABC+ area of "_______"

ABCD is a square . Draw a triangle QBC on side BC considering BC as base and draw a triangle PAC on AC as its base such that Delta QBC ~ Delta PAC . Then, ("Area of " Delta QBC)/("Area of " Delta PAC) is equal to :

Find the area of Fig.34 in the following ways: Sum of the areas of three triangles Area of a rectangle - sum of the areas of five triangles

O' is any point on diagonal AC of a parallelogram ABCD. Prove that : area of Delta AOD = " area of " Delta AOB

ABC is a triangle with base AB. D is a point on AB such that AB = 5 and DB = 3. What is the ratio of the area of Delta ADC to the area of Delta ABC ?