Class 11 Straight lines- find line parallel to another line and one point trick #shorts #cbse #icse

There are 11 points on a plane with 5 lying on one straight line and another 5 lying on a second straight line which is parallel to the first line. The remaining point not collinear with any two in the previous 10 points. The number of triangles that can be formed with vertices chosen from these 11 points

Statement-1 line (x-1)/(3)=(y-2)/(11)=(z+1)/(11) lies in the plane 11x-3z-14=0 . Statement-2 A straight line lies in a plane, if the line is parallel to plane and a point of the line in the plane.

Find the equation of the straight line parallel to the line 3x+4y=7 and passing through the point of intersection of the lines x-2y-3=0 and x+3y-6=0

Straight lines are drawn by joining m points on a straight line of n points on another line. Then excluding the given points, the number of point of intersections of the lines drawn is (no tow lines drawn are parallel and no these lines are concurrent). a. 4m n(m-1)(n-1) b. 1/2m n(m-1)(n-1) c. 1/2m^2n^2 d. 1/4m^2n^2

if the straight line joining the points (3,4) and (2,-1) be parallel to the line joining the points (a,-2) and (4,-a), find the value of a.

There are 10 straight lines in a plane no two of which are parallel and no three are concurrent.The points of intersection are joined,then the number of fresh lines formed are