Class 11 Straight line equation from two points #cbse #icse #shorts

Prove that the locus of the point equidistant from two given points is the straight line which bisects the line segment joining the given points at right angles.

PAIR OF STRAIGHT LINES 11. the equation of one of the line represented ty the eq ial fa) px + qy 0 (b) px-w=0 12. The pair of straight lines passing through th point 1. 2) The pair of straight lines passing through ths point 1. 2)

In the following graph, relation between two variables x and y is shown by a straight line. Equation of the straight line is

The equation of straight line which is equidistant from the points A(2,-2),B(6,1) and C(-3,4) can be

A particle straight line passes through orgin and a point whose abscissa is double of ordinate of the point. The equation of such straight line is :

Find the equations of two straight lines drawn through the point (0,a) such that theperpendiculars from the point (2a,2a) on them are each of length a.Also prove that theequation of the straight line joining the feet of these perpendiculars is y+2x=5a

The point P(a,b) lies on the straight line 3x+2y=13 and the point Q(b,a) lies on the straight line 4x-y=-5 , then the equation of the line PQ is

Equation of the straight line meeting the cirle with centre at origin and radius equal to 5 in two points at equal distances of 3 units from the point (3,4) is

A straight line moves so that the product of the length of the perpendiculars on it from two fixed points is constant.Prove that the locus of the feet of the perpendiculars from each of these points upon the straight line is a unique circle.