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The energy of an electron revolving in n...

The energy of an electron revolving in `n^(th)` Bohr's orbit of an atom is given by the expression

A

`E_(n)=-(2pi^(2)m^(4)e^(2)z^(2))/(n^(2)h^(2))`

B

`E_(n)=-(2pi^(2)me^(2)z^(2))/(n^(2)h^(2))`

C

`E_(n)=-(2pi^(2)me^(4)z^(2)k^(2))/(n^(2)h^(2))`

D

`E_(n)=-(2pim^(2)e^(2)z^(4))/(n^(2)h^(2))`

Text Solution

Verified by Experts

The correct Answer is:
C
By Formula.
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