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The energy of an electron in second Bohr...

The energy of an electron in second Bohr orbit of hydrogen atom is :

A

`-5.44xx10^(-19)J`

B

`-5.44xx10^(-19)kJ`

C

`-5.44xx10^(-19)cal`

D

`-5.44xx10^(-19)eV`

Text Solution

Verified by Experts

The correct Answer is:
A
`E=-(2.172xx10^(-18))/n^(2)=(-2.172xx10^(-18))/2^(2)`
= `-5.44xx10^(-19)J`.
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