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Time taken by an electrons to complete o...

Time taken by an electrons to complete one revolution in the Bohr orbit of the `H` atom is

A

`(4pi^(2)mr^(2))/(nh)`

B

`(nh)/(4pi^(2)mr)`

C

`(nh)/(4pi^(2)mr^(2))`

D

`h/(2pimr)`

Text Solution

Verified by Experts

The correct Answer is:
A
According to Bohr’s model -
`mvr=nh//2pi`
`v=(nh)/(2pimr)`
One revolution = `2pir`
Time taken = `(2pir)/v`
= `(2pirxx2pimr)/(nh)`
= `(4pi^(2)mr^(2))/(nh)`.
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