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The maximum kinetic energy of photoelect...

The maximum kinetic energy of photoelectrons ejected from a metal, when it is irradiated with radiation of frequency `2xx10^(14)s^(-1)` is `6.63xx10^(-20)`J. the threshold frequency of the metal is:

A

`2xx10^(14)s^(-1)`

B

`3xx10^(14)s^(-1)`

C

`2xx10^(-14)s^(-1)`

D

`1xx10^(14)s^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
D
Maximum kinetic energy = Absorbed energy - Threshold energy
`6.63xx10^(-20)J=hv-hv_(0)`
`6.63xx10^(-20)J=h(2xx10^(14)-v_(0))`
`2xx10^(14)-v_(0)=(6.63xx10^(-20))/(6.62xx10^(-34))`
`2xx10^(14)-v_(0)=10^(14)`
`v_(0)=1xx10^(14)s^(-1)`.
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