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The energies E1 and E2 of two radiations...

The energies `E_1` and `E_2` of two radiations are `25 eV` and `50 e V` respectively. The relation between their wavelengths, i.e., `lamda_1` and `lamda_2` will be.

A

`lamda_(1)=1/2lamda_(2)`

B

`lamda_(1)=lamda_(2)`

C

`lamda_(1)=2lamda_(2)`

D

`lamda_(1)=4lamda_(2)`

Text Solution

Verified by Experts

The correct Answer is:
C
`E=hc//lamda`
`Eprop1//lamda` `E_(1)/E_(2)=lamda_(2)/lamda_(1)`
`25/50=lamda_(2)/lamda_(1)`
`lamda_(1)=2lamda_(2)`.
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