What is the maximum number of emission lines are obtained when the excited electron of a H atom in n = 5 drops to the ground state?

Options

A. 10
B. 5
C. 12
D. 15

Answer

A

Explanation

Number of emission lines in the spectrum will be equal to
`((n_(2)-n_(1))(n_(2)-n_(1)+1))/2` where `n_(2)=5` and `n_(1)` = 1.
`therefore((5-1)(5-1+1))/2=20/2` = 10 lines.