The ratio of energy of photon of lambda ...

The ratio of energy of photon of `lambda = 2000 Å` to that of `lambda = 4000 Å` is

A

`1//4`

B

4

C

`1//2`

D

2

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The correct Answer is:

D

`E=hv=h(c)/lamda" "i.e.Eprop1/lamda`
`E_(1)/E_(2)=lamda_(2)/lamda_(1)=4000/2000=2`.

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