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The energy of an electron in the first B...

The energy of an electron in the first Bohr orbit of H atom is `-13.6 eV`. The possible energy value (s) of the excited state (s) for electron in Bohr orbits of hydrogen is (are)

A

`-3.4eV`

B

`-4.2eV`

C

`-6.8eV`

D

`+6.8eV`

Text Solution

Verified by Experts

The correct Answer is:
A
Values of energy in the excited state = `-13.6/n^(2)eV`
= `(-13.6)/4=-3.4eV" "(n=2,3,4" etc".)`
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