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If the ionization energy for the hydroge...

If the ionization energy for the hydrogen atom is 13.6 eV , the energy required to excite it from the ground state to the next higher state is nearly

A

`1.69xx10^(-20)J`

B

`1.69xx10^(-23)J`

C

`1.69xx10^(23)J`

D

`1.69xx10^(25)J`

Text Solution

Verified by Experts

The correct Answer is:
B
`E=(-13.6)/n^(2)=(-13.6)/4=-3.4eV//"atom"`
We know that energy required for excitation
`DeltaE=E_(2)-E_(1)=-3.4-(-13.6)=10.2eV`
Therefore energy required for excitation of electron per atom
= `10.2/(6.02xx10^(23))=1.69xx10^(-23)J`.
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