Home
Class 11
CHEMISTRY
The energy absorbed by each molecule (A2...

The energy absorbed by each molecule `(A_2)` of a substance is `4.4 xx 10^-19 J` and bond energy per molecule is `4.0 xx 10^-19 J`. The kinetic energy of the molecule per atom will be.

A

`2.0xx10^(-20)J`

B

`2.2xx10^(-19)J`

C

`2.0xx10^(-19)J`

D

`4.0xx10^(-20)J`

Text Solution

Verified by Experts

The correct Answer is:
A

K.E per atom = `((4.4xx10^(-19))-(4.0xx10^(-19)))/2`
= `(0.4xx10^(-19))/2=2.0xx10^(-20)`
Promotional Banner

Similar Questions

Explore conceptually related problems

If the energy absorbed by each X, molecule of a gas is 3.5 xx 10^(-19) J and the bond energy of X_2 is 180.6 kJ mol^-1 then the kinetic energy per atom will be

The kinetic energy of N molecules of H_(2) is 3J at -73^(0)C .The kinetic energy of the same sample of H_(2) at 127^(0)C is

The average kinetic energy of gas molecule at 27^(@)C is 6.21xx10^(-21) J. Its average kinetic energy at 127^(@)C will be

The ionisation energy of He^(o+) is 19.6 xx 10^(-18) J atom^(-1) .The energy of the first stationary state of Li^(2+) will be

The average kinetic energy of a hydrogen molecule at 27^(@)C is 9.3 xx 10^(-21) J . The mass of hydrogen molecule is 3.1 xx 10^(-27) kg . (i) Determine the average kinetic en-ergy at 227^(@)C . (ii) Determine the root mean square speed of hydrogen molecule at 27^(@)C .