Home
Class 11
CHEMISTRY
If the radius of the drogen atom is 53 p...

If the radius of the drogen atom is 53 pm, the radius of the `He^(+)` ion is closest to :

A

108 pm

B

81 pm

C

27 pm

D

13 pm

Text Solution

Verified by Experts

The correct Answer is:
C
`r_(He^(o+))=r_(H)xxn^(2)/Z`
`r_(He^(+))=53xx1/2=26.5`pm
It is closest to 27 pm.
Promotional Banner

Similar Questions

Explore conceptually related problems

The radius of first Bohr orbit in H-atom is 0.53 Å. The radius of third orbit is

Calculate the radius of the third orbit of a hydrogen atom the radius of the first Bohr of hydrogen atom is 0.53 Å

Radius of first bohr's orbit of hydrogen atom is 0.53 A then the radius of 3^(rd) bohr orbit is :-

Br^- ions form a close packed structure. If the radius of Br^– ions is 195 pm, calculate the radius of the cation that just fits into the tetrahedral hole. Can a cation A^+ having a radius of 82 pm be shipped into be octahedral hole of the crystal A^+ Br^– ?

" The radius of hydrogen atom in the ground state is "52.9pm" .The radius of the first excited state of He "^(+)" ion will be "

The radius of Bohr 's first orbit in hydrogen atom is 0.53 Å the radius of second orbit in He+ will be

The radus of hydrogen atom in the ground state 0.53 Å . The radius of Li^(2+) ion (Atomic number = 3) in a similar state is

Radius of the first orbit of the electron in a hydrogen atom is 0.53 Å . So, the radius of the third orbit will be