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The energy of a photon wavelength k = 1...

The energy of a photon wavelength `k = 1` meter is (Planck's constant `= 6.625 xx 10^(-34)` Js, speed of light = `3 xx 10^(8) m//s`)

A

`1.988xx10^(-23)J`

B

`1.988xx10^(-28)J`

C

`1.988xx10^(-30)J`

D

`1.988xx10^(-25)J`

Text Solution

Verified by Experts

The correct Answer is:
D
Given `lamda=k=1m" "h=6.625xx10^(-34)Js,c=3xx10^(8)m//s`
`E=(hc)/lamda=(6.625xx10^(-34)Jsxx3xx10^(8)ms^(-1))/(1m)`
= `6.625xx10^(-26)xx3=19.875xx10^(-26)`
= `1.98xx10^(-25)J`.
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