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The set of quantum numbers n=4 , l=0 m=0...

The set of quantum numbers n=4 , l=0 m=0 and `s=+1/2` correspond to the most loosely bound , ground state electron of which one of the following atoms

A

Na

B

Cl

C

Cr

D

Rb

Text Solution

Verified by Experts

The correct Answer is:
C
`""_(11)Nato1s^(2)2s^(2)2p^(6)3s^(1)`
`""_(17)Cl to1s^(2)2s^(2)2p^(6)3s^(2)3p^(5)`
`""_(24)Crto1s^(2)2s^(2)2p^(6)3s^(2)3p^(6)3d^(5)4s^(1)`
`""_(37)Rbto1s^(2)2s^(2)2p^(6)3s^(2)3p^(6)3d^(10)4s^(2)4p^(6)5s^(1)`
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