If `n = 6`, the correct sequence for filling of electrons will be.

Options

A. `nstonpto(n-1)d to(n-2)f`
B. `nsto(n-2)fto(n-1)d tonp`
C. `nsto(n-1)d to(n-2)ftonp`
D. `nsto(n-2)f tonpto(n-1)d`

Answer

B

Explanation

The sequence will be governed by (n + l) rule. Minimum (n + l) to maximum (n + l) and if the value of (n + l) is same then electron will first go to orbital with minimum .n. value.
`nsrArrn+l=6`
`(n-2)f rArrn+l=4+3=7`
`(n-1)drArrn+l=5+2=7`
`nprArrn+l=6+1=7`.