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The wavelength of the radiation emitted ...

The wavelength of the radiation emitted , when in a hydrogen atom electron falls from infinity to stationary state 1 , would be :
(Rydberg constant = `1.097 xx 10^(7) m^(-1)`)

Text Solution

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The correct Answer is:
91
`barv=1/lamda=R(1/n_1^2-1/n_2^2)`
`=1.097 xx10^7m^(-1)(1/1^2 -1/oo^2)=1.097 xx10^7m^(-1)`
or `lamda=1/(1.097 xx10^(7))m=0.91 xx10^(-7)m =91 nm`
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