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If first orbit energy of He^(+) is -54.4...

If first orbit energy of `He^(+)` is -54.4 eV, then the second orbit energy will be

A

`- 54.4 eV`

B

`-13.6 eV`

C

`- 27.2 eV `

D

`+ 27.2 eV`

Text Solution

Verified by Experts

The correct Answer is:
B
`E=E_(0)/n^2 = (-54.4)/4 = -13.6 eV`
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