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The ground state energy of hydrogen atom...

The ground state energy of hydrogen atom is `-13.6 eV`. The energy of second excited state of `He^(+)` ion in eV is

A

`-27.2 `

B

`-54.4 `

C

`-3.4 `

D

`-6.04`

Text Solution

Verified by Experts

The correct Answer is:
D
`E=-13.6(Z^2/n^2)=-13.6 (2^2/3^2)=-6.04 eV`
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