Home
Class 11
CHEMISTRY
The ratio of te shortest wavelength of t...

The ratio of te shortest wavelength of two spectral series of hydrogen spectrum is found to be about 9. The spectral series are:

A

Paschen and Pfund

B

Brackett and Pfund

C

Lyman and Paschen

D

Balmer and Brackett

Text Solution

Verified by Experts

The correct Answer is:
C
Shortest `lamda` for lyman series :
`1/lamda=R(1/1^2-1/oo)=R,lamda=1/R`
shortest `lamda` for paschen series :
`1/(lamda.)=R(1/3^2-1/oo)=R/9,lamda.=9/R`
`(lamda.)/lamda=9/RxxR/1=9`
Promotional Banner

Similar Questions

Explore conceptually related problems

The ratio of the largest to shortest wavelength in Lyman series of hydrogen spectra is

The ratio of the largest to shortest wavelength in Balmer series of hydrogen spectra is,

The ratio of the longest to shortest wavelength in Brackett series of hydrogen spectra is

Spectral Series Of Hydrogen Atom

Spectral Series Of Hydrogen Atom

Which is the shortest wavelength in the Balmer series of hydrogen atoms ?

The lagest and shortest wavelengths in the Lyman series for hydrogen

Spectral series of spectrum