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The de Broglie wavelenght (lambda) assoc...

The de Broglie wavelenght `(lambda)` associated with a photoelectron varies with the frequency `(v)` of the incident radiation as,[`v_(0)` is threshold frequency]:

A

`lamdaprop1/((v-v_0)^(3/2))`

B

`lamdaprop1/((v-v_0))`

C

`lamdaprop1/((v-v_0)^(1/2))`

D

`lamdaprop1/((v-v_0)^(1/4))`

Text Solution

Verified by Experts

The correct Answer is:
C
`hv = hv_0 +1/2 mv^2`
`h(v-v_0) =1/2mv^2`
`v=((2h(v-v_0))/m)^(1//2)`
`lamda=h/(mv)=h/m=sqrtm/(sqrt(2h(v-v_0)))=sqrt(h/(m(v-v_0))`
`lamda prop 1/((v-v_0)^(1//2))`
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