The kinetic energy of an electron in the second Bohr orbit of a hydrogen atom is equal to `(h^(2))/(x ma_(0)^(2))`. The value of 10x is __________. (`a_(0)` is radius of Bohr's orbit)
(Nearest integer)
[Given : `pi=3.14`]

Answer

3155

Explanation

`mvr=(nh)/(2pi)`
`=(n^2h^2)/(8pi^2)=(4h^2)/(8pi^2m(4a_0)^2)`
`= ((4)/(8pixx16))h^2/(ma_0^2)`
`implies x = 315.507`
`implies 10 x = 3155` (nearest integer)